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MHT CET · Physics · Wave Optics

In Young's double slit interference experiment, using two coherent sources of different amplitudes, the intensity ratio between bright to dark fringes is \(5: 1\). The value of the ratio of resultant amplitudes of bright fringe to dark fringe is

  1. A \(\left(\frac{\sqrt{5}+1}{\sqrt{5}-1}\right)\)
  2. B \(\sqrt{5}: 1\)
  3. C \(\left(\frac{\sqrt{5}-1}{\sqrt{5}+1}\right)\)
  4. D \(1: \sqrt{5}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sqrt{5}: 1\)

Step-by-step Solution

Detailed explanation

\(\frac{I_{max}}{I_{min}} = \left(\frac{A_{max}}{A_{min}}\right)^2\) \(5 = \left(\frac{A_{max}}{A_{min}}\right)^2\)
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