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MHT CET · Physics · Wave Optics

In Young's double slit experiment with monochromatic light of wavelength 600 nm, the distance between the slits is \(10^{-3} \mathrm{~m}\). For changing the fringe width by \(3 \times 10^{-5} \mathrm{~m}\)
a) the screen is moved away from the slit by 5 cm.
b) the screen is moved 5 cm towards the slits.
c) the screen is moved 3 cm towards the slits.
d) the screen is moved away from the slits by 3 cm.

  1. A both (c) and (d)
  2. B both (a) and (b)
  3. C only (a)
  4. D only (c)
Verified Solution

Answer & Solution

Correct Answer

(B) both (a) and (b)

Step-by-step Solution

Detailed explanation

\(\Delta D = \frac{\Delta \beta \cdot d}{\lambda}\) \(\Delta D = \frac{(3 \times 10^{-5} \mathrm{~m}) \cdot (10^{-3} \mathrm{~m})}{600 \times 10^{-9} \mathrm{~m}}\)