MHT CET · Physics · Wave Optics
In Young's double Slit experiment, we get 15 fringes per \(\mathrm{cm}\) on the screen using light of wave length \(560\)Å. For the same setting how many fringes per \(\mathrm{cm}\) will be obtained with the light of wavelength \(7000\)Å ?
- A \(18\)
- B \(10\)
- C \(12\)
- D \(15\)
Answer & Solution
Correct Answer
(C) \(12\)
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{X}_2}{\mathrm{X}_1}=\frac{\lambda_2}{\lambda_2} \)
\( \therefore \frac{\mathrm{X}_2}{\frac{1}{15}}=\frac{5}{4} \)
\( 15 \mathrm{X}_2=\frac{5}{4} \)
\( \therefore \mathrm{X}_2=\frac{1}{12} \text { cm } \)
\( \therefore \text { No. off fringes per cm }=12\)
\( \therefore \frac{\mathrm{X}_2}{\frac{1}{15}}=\frac{5}{4} \)
\( 15 \mathrm{X}_2=\frac{5}{4} \)
\( \therefore \mathrm{X}_2=\frac{1}{12} \text { cm } \)
\( \therefore \text { No. off fringes per cm }=12\)
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