MHT CET · Physics · Wave Optics
In Young's double slit experiment the wavelength of light used is \(6000 Å\), the screen is 40 cm from the slits and the fringe width is 0.012 cm , the distance between two slits is
- A 0.024 cm
- B 2.4 cm
- C 0.24 cm
- D 0.2 cm
Answer & Solution
Correct Answer
(D) 0.2 cm
Step-by-step Solution
Detailed explanation
\( d = \frac{\lambda D}{\beta} \) \( d = \frac{(6000 \times 10^{-8} \text{ cm}) \times (40 \text{ cm})}{0.012 \text{ cm}} \)
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