MHT CET · Physics · Wave Optics
In Young's double slit experiment, the distance between the slits is 2 mm and the slits are 1 m away, from the screen. Two interference patterns can be obtained on the screen due to light of wavelength ' \(\lambda_1\) ' and ' \(\lambda_2\) ' respectively. The separation on the screen between the \(3^{\text {rd }}\) order bright fringes on the two interference patterns is ( \(\lambda_2=1 \cdot 5 \lambda_1\) )
- A \(\left(0.75 \times 10^{+3}\right) \lambda_1\)
- B \(\left(1 \cdot 75 \times 10^{+3}\right) \lambda_1\)
- C \(\left(2 \cdot 00 \times 10^{+3}\right) \lambda_1\)
- D \(\left(2 \cdot 25 \times 10^{+3}\right) \lambda_1\)
Answer & Solution
Correct Answer
(A) \(\left(0.75 \times 10^{+3}\right) \lambda_1\)
Step-by-step Solution
Detailed explanation
\(y_n = \frac{n \lambda D}{d}\) \(\Delta y = y_3(\lambda_2) - y_3(\lambda_1) = \frac{3 \lambda_2 D}{d} - \frac{3 \lambda_1 D}{d}\)
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