MHT CET · Physics · Wave Optics
In Young's double slit experiment, the \(10^{\text {th }}\) maximum of wavelength ' \(\lambda_1\) ' is at a distance of ' \(\mathrm{Y}_1\) ' from the central maximum. When the wavelength of the source is changed to ' \(\lambda_2\) ', \(5^{\text {th }}\) maximum is at a distance ' \(Y_2\) ' from the central maximum. The ratio \(\frac{\mathrm{Y}_1}{\mathrm{Y}_2}\) is
- A \(\frac{2 \lambda_1}{\lambda_2}\)
- B \(\frac{\lambda_2}{2 \lambda_1}\)
- C \(\frac{2 \lambda_2}{\lambda_1}\)
- D \(\frac{\lambda_1}{2 \lambda_2}\)
Answer & Solution
Correct Answer
(A) \(\frac{2 \lambda_1}{\lambda_2}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & Y_1=\frac{10 \lambda_1 D}{d}, Y_2=\frac{5 \lambda_2 D}{d} \\ & \therefore \frac{Y_1}{Y_2}=\frac{10 \lambda_1}{5 \lambda_2}=\frac{2 \lambda_1}{\lambda_2}\end{aligned}\)
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