MHT CET · Physics · Wave Optics
In Young's double slit experiment let 'd' be the distance between two slits and 'D' be the distance between the slits and the screen. Using a monochromatic source of wavelength ' \(\lambda\) ', in an interference pattern, third minimum is observed exactly in front of one of the slits. If at the same point on the screen first minimum is to be obtained, the required change in the wavelength is [d & D are not changed]
- A \(2 \lambda\)
- B \(3 \lambda\)
- C \(4 \lambda\)
- D \(5 \lambda\)
Answer & Solution
Correct Answer
(C) \(4 \lambda\)
Step-by-step Solution
Detailed explanation
\(\text{For nth minimum: } y_n = (n - 0.5) \frac{\lambda D}{d}\) \(\text{Third minimum at } y = d/2\text{ (n=3): } \frac{d}{2} = (3 - 0.5) \frac{\lambda D}{d}\)
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