MHT CET · Physics · Wave Optics

In Young's double-slit experiment, in an interference pattern, the second minimum is observed exactly in front of one slit. The distance between the slits is $d$ and the distance between source and screen is $D$ . The wavelength of the light source used is

A $\frac{d^{2}}{D}$
B $\frac{d^{2}}{2 D}$
C $\frac{d^{2}}{3 D}$
D $\frac{d^{2}}{4 D}$

Verified Solution

Answer & Solution

Correct Answer

(C) $\frac{d^{2}}{3 D}$

Step-by-step Solution

Detailed explanation

Distance of second minima from central point is

y = \frac{d}{2}

. We know that minima is given by,

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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In Young's double-slit experiment, in an interference pattern, the second minimum is observed exactly in front of one slit. The distance between the slits is d and the distance between source and screen is D. The wavelength of the light source used is

Step-by-step Solution

In Young's double-slit experiment, in an interference pattern, the second minimum is observed exactly in front of one slit. The distance between the slits is $d$ and the distance between source and screen is $D$ . The wavelength of the light source used is