MHT CET · Physics · Wave Optics
In Young's double slit experiment, in an interference pattern second minimum is observed exactly in from of one slit. The distance between the two coherent sources is ' d ' and the distance between source and screen is 'D'. The wavelength of light source used is
- A \(\frac{\mathrm{d}^2}{4 \mathrm{D}}\)
- B \(\frac{\mathrm{d}^2}{3 \mathrm{D}}\)
- C \(\frac{\mathrm{d}^2}{2 \mathrm{D}}\)
- D \(\frac{\mathrm{d}^2}{\mathrm{D}}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{d}^2}{3 \mathrm{D}}\)
Step-by-step Solution
Detailed explanation
Path difference for second minimum: \(\Delta L = (1 + 1/2)\lambda = 3\lambda/2\) Position on screen: \(y = d/2\)
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