MHT CET · Physics · Wave Optics
In Young's double slit experiment, for the \(n\)th dark fringe ( \(n=1,2,3 \ldots\) ) the phase difference of the interfering waves in radian will be
- A \(n \frac{\pi}{2}\)
- B \((2 n+1) \pi\)
- C \((2 n-1) \pi\)
- D \((2 n-1) \frac{\pi}{2}\)
Answer & Solution
Correct Answer
(C) \((2 n-1) \pi\)
Step-by-step Solution
Detailed explanation
Phase difference \( \Delta \phi = \frac{2\pi}{\lambda} \Delta x \) For \(n\)th dark fringe, path difference \( \Delta x = (2n-1)\frac{\lambda}{2} \)
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