MHT CET · Physics · Wave Optics
In Young's double slit experiment, at two points P and Q on screen, waves from slits \(s_1\) and \(s_2\) have a path difference of 0 and \(\frac{\lambda}{4}\) respectively. The ratio of intensities at point \(P\) to that at \(Q\) will be \(\left(\cos 0^{\circ}=1, \cos 45^{\circ}=\frac{1}{\sqrt{2}}\right)\)
- A \(3: 2\)
- B \(2: 1\)
- C \(\sqrt{2}: 1\)
- D \(4: 1\)
Answer & Solution
Correct Answer
(B) \(2: 1\)
Step-by-step Solution
Detailed explanation
\(I = I_{max} \cos^2\left(\frac{\pi \Delta x}{\lambda}\right)\) \(I_P = I_{max} \cos^2\left(\frac{\pi (0)}{\lambda}\right) = I_{max} \cos^2(0) = I_{max}\)
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