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MHT CET · Physics · Wave Optics

In Young' double slit experiment, for the \(n^{\text {th }}\) dark fringe ( \(n=1,2,3\).....) the phase difference of the interfering waves in radian will be

  1. A \((2 n-1) \pi\)
  2. B \((2 n+1) \pi\)
  3. C \(\mathrm{n} \frac{\pi}{2}\)
  4. D \((2 n-1) \frac{\pi}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \((2 n+1) \pi\)

Step-by-step Solution

Detailed explanation

The resultant intensity of the interfering waves is given by,
\(\mathrm{E}^2 \mathrm{E}_1^2+\mathrm{E}_2^2+2 \mathrm{E}_1 \mathrm{E}_2 \cos (\delta)\)
where, \(\delta\) is the phase difference between the waves.
For a dark fringe, \(\mathrm{E}_1=\mathrm{E}_2\) and \(\cos (\delta)=-1\).
Therefore, the phase \(\delta=(2 n+1) \pi\) is an odd multiple of pi.
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