MHT CET · Physics · Semiconductors
In transistor amplifier, base-emitter junction is forward biased and collector emitter junction is reverse biased. The current gain is
- A \(\frac{\Delta \mathrm{I}_{\mathrm{E}}}{\Delta \mathrm{I}_{\mathrm{B}}}\)
- B \(\frac{\Delta \mathrm{I}_{\mathrm{B}}}{\Delta \mathrm{I}_{\mathrm{E}}}\)
- C \(\frac{\Delta \mathrm{I}_{\mathrm{B}}}{\Delta \mathrm{I}_{\mathrm{C}}}\)
- D \(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\)
Answer & Solution
Correct Answer
(D) \(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\)
Step-by-step Solution
Detailed explanation
\(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\)
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