MHT CET · Physics · Semiconductors

In the study of transistor as an amplifier, the ratio of collector current to emitter current is 0.98 then the ratio of collector current to base current will be

A 99
B 49
C 50
D 98

Verified Solution

Answer & Solution

Correct Answer

(B) 49

Step-by-step Solution

Detailed explanation

The ratio of collector current to emitter current at constant collector base voltage is the current the amplification factor and given by

α = \frac{l_{C}}{l_{E}} = 0.98

(Given)
The ratio of collector current to the base current at constant collector-emitter voltage is given by

β = \frac{l_{C}}{l_{B}}

These are related as

β = \frac{α}{1 - α}

\Rightarrow β = \frac{0.98}{1 - 0.98} = \frac{0.98}{0.02} = 49

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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