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MHT CET · Physics · Semiconductors

In the study of transistor as an amplifier if \(\alpha=\frac{I_C}{I_E}=0.98\) and \(\beta=\frac{I_C}{I_B}=49\), where \(I_C, I_B\) and \(\mathrm{I}_{\mathrm{E}}\) are cóllector, base and emitter current respectively then \(\left(\frac{1}{\alpha}-\frac{1}{\beta}\right)\) is equal to

  1. A zero
  2. B \(\frac{1}{2}\)
  3. C \(2\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} \frac{1}{\alpha}-\frac{1}{\beta} & =\frac{1}{0.98}-\frac{1}{4.9} \\ & =1.204-0.204=1\end{aligned}\)
From MHT CET
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