MHT CET · Physics · Alternating Current
In the given circuit, when \(\mathrm{S}_1\) is closed, the capacitor gets fully charged. Now \(\mathrm{S}_1\) is open and \(\mathrm{S}_2\) is closed. Then

- A there is no exchange of energy between L and C .
- B the current in the circuit is in the same direction.
- C the instantaneous current in the circuit may be \(\mathrm{V}\left(\sqrt{\frac{\mathrm{C}}{\mathrm{L}}}\right)\).
- D the energy stored in the circuit is purely in the form of magnetic energy.
Answer & Solution
Correct Answer
(C) the instantaneous current in the circuit may be \(\mathrm{V}\left(\sqrt{\frac{\mathrm{C}}{\mathrm{L}}}\right)\).
Step-by-step Solution
Detailed explanation
Maximum energy in capacitor \(=\) Maximum energy in inductor
\(\frac{1}{2} \mathrm{CV}^2=\frac{1}{2} \mathrm{LI}^2\)
\(\begin{array}{ll}\therefore & I^2=\frac{C}{L} V^2 \\ \therefore & I=V \sqrt{\frac{C}{L}}\end{array}\)
\(\frac{1}{2} \mathrm{CV}^2=\frac{1}{2} \mathrm{LI}^2\)
\(\begin{array}{ll}\therefore & I^2=\frac{C}{L} V^2 \\ \therefore & I=V \sqrt{\frac{C}{L}}\end{array}\)
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