MHT CET · Physics · Current Electricity
In the given circuit, the current in \(8 \Omega\) resistance is \(1.5 \mathrm{~A}\). The total current (I) flowing in the circuit is
- A 5 A
- B 4.5 A
- C 3 A
- D 5.5 A
Answer & Solution
Correct Answer
(D) 5.5 A
Step-by-step Solution
Detailed explanation
\(
\mathrm{I}_1=1.5 \mathrm{~A}, \mathrm{R}_1=8 \Omega
\)
P.D. across \(\mathrm{R}_1=1.5 \times 8=12 \mathrm{~V}\)
\(R_2=3 \Omega ; R_2\) is in parallel with \(R_1\) and hence P.D. across it is also \(12 \mathrm{~V}\).
\(
\therefore \mathrm{I}_2=\frac{12}{3}=4 \mathrm{~A}
\)
Total current \(\mathrm{I}=\mathrm{I}_1+\mathrm{I}_2=1.5+4=5.5 \mathrm{~A}\)
\mathrm{I}_1=1.5 \mathrm{~A}, \mathrm{R}_1=8 \Omega
\)
P.D. across \(\mathrm{R}_1=1.5 \times 8=12 \mathrm{~V}\)
\(R_2=3 \Omega ; R_2\) is in parallel with \(R_1\) and hence P.D. across it is also \(12 \mathrm{~V}\).
\(
\therefore \mathrm{I}_2=\frac{12}{3}=4 \mathrm{~A}
\)
Total current \(\mathrm{I}=\mathrm{I}_1+\mathrm{I}_2=1.5+4=5.5 \mathrm{~A}\)
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