MHT CET · Physics · Alternating Current
In the given circuit, r.m.s. value of current through the resistor \(\mathrm{R}\) is

- A \(2 \mathrm{~A}\)
- B \(0.5 \mathrm{~A}\)
- C \(20\mathrm{~A}\)
- D \(2 \sqrt{2} \mathrm{~A}\)
Answer & Solution
Correct Answer
(A) \(2 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{Z} & =\sqrt{\mathrm{R}^2+\left(\mathrm{X}_{\mathrm{L}}-\mathrm{X}_{\mathrm{C}}\right)^2} \\ \mathrm{Z} & =\sqrt{100^2+100^2} \\ \mathrm{Z} & =100 \sqrt{2} \Omega \\ \mathrm{i}_{\mathrm{rms}} & =\frac{\mathrm{V}_{\mathrm{rms}}}{\mathrm{Z}} \\ \therefore \quad \mathrm{i}_{\mathrm{rms}} & =\frac{200 \sqrt{2}}{100 \sqrt{2}} \\ \mathrm{i}_{\mathrm{rms}} & =2 \mathrm{~A}\end{aligned}\)
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