MHT CET · Physics · Current Electricity
In the given circuit, if \(\frac{\mathrm{dI}}{\mathrm{dt}}=-1 \mathrm{~A} / \mathrm{s}\) then the value of \(\left(V_A-V_B\right)\) at this instance will be
- A \(30 \mathrm{~V}\)
- B \(24 \mathrm{~V}\)
- C \(18 \mathrm{~V}\)
- D \(9 \mathrm{~V}\)
Answer & Solution
Correct Answer
(A) \(30 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Applying KVL in the given circuit from point \(A\) to \(\mathrm{B}\),
\(
\begin{array}{ll}
& \mathrm{V}_{\mathrm{AB}}-\mathrm{IR}-\mathrm{L} \frac{\mathrm{dI}}{\mathrm{dt}}-12=0 \\
& \mathrm{~V}_{\mathrm{AB}}-(2)(12)-6(-1)-12=0 \\
& \mathrm{~V}_{\mathrm{AB}}=24+12-6 \\
\therefore & \mathrm{V}_{\mathrm{AB}}=30 \mathrm{~V}
\end{array}
\)
\(
\begin{array}{ll}
& \mathrm{V}_{\mathrm{AB}}-\mathrm{IR}-\mathrm{L} \frac{\mathrm{dI}}{\mathrm{dt}}-12=0 \\
& \mathrm{~V}_{\mathrm{AB}}-(2)(12)-6(-1)-12=0 \\
& \mathrm{~V}_{\mathrm{AB}}=24+12-6 \\
\therefore & \mathrm{V}_{\mathrm{AB}}=30 \mathrm{~V}
\end{array}
\)
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