MHT CET · Physics · Semiconductors
In the following combination of logic gates, the output \(Y\) can be written in the terms of inputs A and B as

- A \((\mathrm{A} \cdot \overline{\mathrm{B}})+(\overline{\mathrm{A}} \cdot \mathrm{B})\)
- B \((\mathrm{A} \cdot \mathrm{B})+(\overline{\mathrm{A}} \cdot \mathrm{B})\)
- C \((\overline{\mathrm{A} \cdot \mathrm{B}})+(\overline{\mathrm{A}} \cdot \mathrm{B})\)
- D \((\overline{\mathrm{A} \cdot \mathrm{B}})+(\mathrm{A} \cdot \overline{\mathrm{B}})\)
Answer & Solution
Correct Answer
(C) \((\overline{\mathrm{A} \cdot \mathrm{B}})+(\overline{\mathrm{A}} \cdot \mathrm{B})\)
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