MHT CET · Physics · Semiconductors
In the digital circuit the inputs are as shown in figure. The Boolean expression for output \(\mathrm{Y}\) is
- A \(\overline{\mathrm{A}+\mathrm{B}}+\overline{\mathrm{C}}\)
- B \(\overline{\mathrm{A} \cdot \mathrm{B}} \cdot \overline{\mathrm{C}}\)
- C \(\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\mathrm{C}}\)
- D \(\overline{\mathrm{A}+\mathrm{B}} \cdot \overline{\mathrm{C}}\)
Answer & Solution
Correct Answer
(C) \(\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\mathrm{C}}\)
Step-by-step Solution
Detailed explanation
In the given circuit, there is AND, NOR and a NOT gate.
Output of AND gate: \(\overline{\mathrm{A} \cdot \mathrm{B}}\)
Output of NOT gate: \(\overline{\mathrm{C}}\)
\(\therefore \quad\) The boolean expression will be:
\(\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\mathrm{C}}\)
Output of AND gate: \(\overline{\mathrm{A} \cdot \mathrm{B}}\)
Output of NOT gate: \(\overline{\mathrm{C}}\)
\(\therefore \quad\) The boolean expression will be:
\(\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\mathrm{C}}\)
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