MHT CET · Physics · Semiconductors
In the common emitter mode of a transistor when the collector emitter voltage is changed by \(0.4 \mathrm{~V}\), the collector current changes by \(0.04 \mathrm{~mA}\). The output resistance is
- A \(20 \mathrm{k} \Omega\)
- B \(10 \mathrm{k} \Omega\)
- C \(5 \mathrm{k} \Omega\)
- D \(1 \mathrm{k} \Omega\)
Answer & Solution
Correct Answer
(B) \(10 \mathrm{k} \Omega\)
Step-by-step Solution
Detailed explanation
The output resistance is given by
\(R=\frac{\Delta V}{\Delta I}=\frac{0.4}{0.04 \times 10^{-3}}=10 \mathrm{k} \Omega\)
\(R=\frac{\Delta V}{\Delta I}=\frac{0.4}{0.04 \times 10^{-3}}=10 \mathrm{k} \Omega\)
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