MHT CET · Physics · Capacitance
In the circuit shown in the following figure, the potential difference cross \(3 \mu \mathrm{~F}\) capacitor is
- A 4 V
- B 6 V
- C 10 V
- D 16 V
Answer & Solution
Correct Answer
(C) 10 V
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& V_{e q}=20-4 \\
& =16 \mathrm{~V} \\
& \mathrm{C}_{\mathrm{eq}}=\frac{3 \times 5}{3+5} \\
& =\frac{15}{8} \\
& \mathrm{Q}=\mathrm{C}_{\mathrm{eq}} \times \mathrm{V}_{\mathrm{eq}} \\
& =\frac{15}{8} \times 16 \\
& =30 \mathrm{C} \\
& \dot{\mathrm{~V}}_3=\frac{\mathrm{Q}}{\mathrm{C}}=\frac{30}{3}=10 \mathrm{~V}
\end{aligned}\)
& V_{e q}=20-4 \\
& =16 \mathrm{~V} \\
& \mathrm{C}_{\mathrm{eq}}=\frac{3 \times 5}{3+5} \\
& =\frac{15}{8} \\
& \mathrm{Q}=\mathrm{C}_{\mathrm{eq}} \times \mathrm{V}_{\mathrm{eq}} \\
& =\frac{15}{8} \times 16 \\
& =30 \mathrm{C} \\
& \dot{\mathrm{~V}}_3=\frac{\mathrm{Q}}{\mathrm{C}}=\frac{30}{3}=10 \mathrm{~V}
\end{aligned}\)
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