MHT CET · Physics · Waves and Sound
In sine wave, minimum distance between 2 particles always having same speed is
- A \(\frac{\lambda}{2}\)
- B \(\frac{\lambda}{4}\)
- C \(\frac{\lambda}{3}\)
- D \(\lambda\)
Answer & Solution
Correct Answer
(A) \(\frac{\lambda}{2}\)
Step-by-step Solution
Detailed explanation
Sine wave
Particle velocity \(v_{p}=\frac{d y}{d t}=\) slope of wave at that point. As slope at \(A\) and \(B\) is zero. Hence the velocity at \(A\) and \(B\) will be same. Distance between \(A\) and \(B\)
\(
\text { is } \frac{\lambda}{2}
\)
Particle velocity \(v_{p}=\frac{d y}{d t}=\) slope of wave at that point. As slope at \(A\) and \(B\) is zero. Hence the velocity at \(A\) and \(B\) will be same. Distance between \(A\) and \(B\)
\(
\text { is } \frac{\lambda}{2}
\)
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