MHT CET · Physics · Alternating Current
In series LCR resonant circuit; the capacitance is changed from C to 3 C . To obtain the same resonant frequency, the inductance should be changed from \(L\) to
- A \(\frac{\mathrm{L}}{3}\)
- B \(\frac{\mathrm{L}}{2}\)
- C \(\frac{\mathrm{L}}{\sqrt{3}}\)
- D 3 L
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{L}}{3}\)
Step-by-step Solution
Detailed explanation
At resonance,
\(\begin{array}{ll}
& \mathrm{X}_{\mathrm{L}}=\mathrm{X}_{\mathrm{C}} \\
\therefore & \omega \mathrm{~L}=\frac{1}{\omega \mathrm{C}} \\
\therefore & \mathrm{~L} \propto \frac{1}{\mathrm{C}}
\end{array}\)
\(\therefore \quad\) When C is changed to 3 C , L should be \(\frac{\mathrm{L}}{3}\)
\(\begin{array}{ll}
& \mathrm{X}_{\mathrm{L}}=\mathrm{X}_{\mathrm{C}} \\
\therefore & \omega \mathrm{~L}=\frac{1}{\omega \mathrm{C}} \\
\therefore & \mathrm{~L} \propto \frac{1}{\mathrm{C}}
\end{array}\)
\(\therefore \quad\) When C is changed to 3 C , L should be \(\frac{\mathrm{L}}{3}\)
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