MHT CET · Physics · Oscillations

In S.H.M. the displacement of a particle at an instant is \(\mathrm{Y}=\mathrm{A} \cos 30^{\circ}\), where \(\mathrm{A}=40 \mathrm{~cm}\) and kinetic energy is 200 J . If force constant is \(1 \times 10^{\mathrm{x}} \mathrm{N} / \mathrm{m}\), then x will be \(\left(\cos 30^{\circ}=\sqrt{3} / 2\right)\)

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Answer & Solution

Correct Answer

(A) 4

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & Y=A \cos 30^{\circ}=40 \times \frac{\sqrt{3}}{2}=20 \sqrt{3} \mathrm{~cm} \\ & \text { K.E. }=\frac{1}{2} k\left(A^2-Y^2\right) \\ & 200=\frac{1}{2} k\left(\frac{1600}{10^4}-\frac{1200}{10^4}\right)\end{aligned}\)
\(\begin{aligned} & 200=\frac{1}{2} k\left(\frac{400}{10^4}\right) \\ & k=10000=1 \times 10^4 \\ \therefore \quad & x=4\end{aligned}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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