MHT CET · Physics · Oscillations
In S.H.M. a simple pendulum oscillates with frequency \(f\). If the length of the pendulum is increased by three times its original length, then the frequency of oscillation of the pendulum will be
- A \(4 f\)
- B \(2 f\)
- C \(f\)
- D \(\frac{f}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{f}{2}\)
Step-by-step Solution
Detailed explanation
\(T \propto \sqrt{l}\) or \(f \propto 1 / \sqrt{l}\)
If the length is increased by three times the original length, then the new length is four times the original length.
\(\frac{f_1}{f}=\sqrt{\frac{l}{4 l}}=\frac{1}{2}\)
If the length is increased by three times the original length, then the new length is four times the original length.
\(\frac{f_1}{f}=\sqrt{\frac{l}{4 l}}=\frac{1}{2}\)
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