MHT CET · Physics · Waves and Sound
In resonance tube of length \(0.8 \mathrm{~m}\), air column vibrates with a source of frequency
\(375 \mathrm{~Hz}\) for a certain height of water from bottom of the tube. Water level corresponding to fundamental frequency is (Neglect end correction, speed of sound in air = \(330 \mathrm{~m} / \mathrm{s}\) )
- A \(0.45 \mathrm{~m}\)
- B \(0.58 \mathrm{~m}\)
- C \(0.8 \mathrm{~m}\)
- D \(0.65 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(0.58 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\ell=0.8 \mathrm{~m} \quad \mathrm{f}=375 \mathrm{~Hz} \quad \mathrm{v}=330 \mathrm{~m}\)
\(\mathrm{n}_{0}=\frac{\mathrm{v}}{4 \ell}=375\)
\(\therefore \ell=\frac{330}{4 \times 375}=0.22 \mathrm{~m}\)
\(\therefore \mathrm{L}-\ell=0.8-0.22 \mathrm{~m}=0.58 \mathrm{~m}\)
\(\mathrm{n}_{0}=\frac{\mathrm{v}}{4 \ell}=375\)
\(\therefore \ell=\frac{330}{4 \times 375}=0.22 \mathrm{~m}\)
\(\therefore \mathrm{L}-\ell=0.8-0.22 \mathrm{~m}=0.58 \mathrm{~m}\)
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