MHT CET · Physics · Current Electricity
In potentiometer experiment, the balancing length is \(8 \mathrm{~m}\) when two cells \(E_1\) and \(E_2\) are joined in series. When two cells are connected in opposition the balancing length is \(4 \mathrm{~m}\). The ratio of the e.m.f. of the two cells \(\left(\frac{E_1}{E_2}\right)\) is
- A \(1:2\)
- B \(2:1\)
- C \(1:3\)
- D \(3:1\)
Answer & Solution
Correct Answer
(D) \(3:1\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{\mathrm{E}_1}{\mathrm{E}_2}=\frac{l_1+l_2}{l_1-l_2}=\frac{8+4}{8-4} \\ & \frac{\mathrm{E}_1}{\mathrm{E}_2}=\frac{12}{4} \\ \therefore \quad \frac{\mathrm{E}_1}{\mathrm{E}_2} & =3\end{aligned}\)
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