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MHT CET · Physics · Current Electricity

In potentiometer experiment, cells of e.m.f. ' \(E_1\) ' and ' \(E_2\) ' are connected in series \(\left(E_1>E_2\right)\) the balancing length is \(64 \mathrm{~cm}\) of the wire. If the polarity of \(\mathrm{E}_2\) is reversed, the balancing length becomes \(32 \mathrm{~cm}\). The ratio \(\frac{E_1}{E_2}\) is

  1. A \(1: 1\)
  2. B \(6: 1\)
  3. C \(3: 1\)
  4. D \(2: 1\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3: 1\)

Step-by-step Solution

Detailed explanation

\(\frac{E_1}{E_2}=\frac{\ell_1+\ell_2}{\ell_1-\ell_2}=\frac{64+32}{64-32}=\frac{96}{32}=3\)