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MHT CET · Physics · Atomic Physics

In Paschen series, wavelength of first line is ' \(\lambda_1\) ' and for Brackett series, wavelength of first line is ' \(\lambda_2\) ' then ratio \(\frac{\lambda_1}{\lambda_2}\) is

  1. A \(\frac{7}{400}\)
  2. B \(\frac{9}{144}\)
  3. C \(\frac{81}{175}\)
  4. D \(\frac{108}{509}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{81}{175}\)

Step-by-step Solution

Detailed explanation

For Paschen series (first line): \(n_f=3, n_i=4\) \(\frac{1}{\lambda_1} = R\left(\frac{1}{3^2} - \frac{1}{4^2}\right) = R\left(\frac{1}{9} - \frac{1}{16}\right) = R\left(\frac{16-9}{144}\right) = \frac{7R}{144}\)
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