MHT CET · Physics · Rotational Motion
In \(\mathrm{P}^{\text {th }}\) second, a particle describes angular displacement of ' \(\beta\) ' rad. If it starts from rest, the angular acceleration is
- A \(\frac{\beta}{P}\)
- B \(\frac{\beta}{(P-1)}\)
- C \(\frac{2 \beta}{(2 P-1)}\)
- D \(\frac{(2 \beta+1)}{(2 \mathrm{P}-1)}\)
Answer & Solution
Correct Answer
(C) \(\frac{2 \beta}{(2 P-1)}\)
Step-by-step Solution
Detailed explanation
The equation for the angular displacement of the particle that starts from rest is given as:
\(\beta=0+\frac{1}{2} \alpha(2 \mathrm{P}-1)\)
\(\therefore\) The angular acceleration of the particle is \(\alpha=\frac{2 \beta}{(2 \mathrm{P}-1)}\)
\(\beta=0+\frac{1}{2} \alpha(2 \mathrm{P}-1)\)
\(\therefore\) The angular acceleration of the particle is \(\alpha=\frac{2 \beta}{(2 \mathrm{P}-1)}\)
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