MHT CET · Physics · Waves and Sound
In melde's experiment, when the tension decreases by \(0.009\) kg-wt, the number of
loops changes from 4 to \(5 .\) The initial tension is
- A \(0.036\) kg-wt.
- B \(0 \cdot 009 \mathrm{~kg}\) -wt.
- C \(0 \cdot 018\) kg-wt.
- D \(0.025\) kg-wt.
Answer & Solution
Correct Answer
(D) \(0.025\) kg-wt.
Step-by-step Solution
Detailed explanation
For Melde's experiment. \(\mathrm{TP}^{2}=\) constant where \(\mathrm{T}\) is the tension and \(\mathrm{P}\) is the number of loops.
\(
\begin{array}{l}
\therefore \mathrm{T}_{1} \mathrm{P}_{1}{ }^{2}=\mathrm{T}_{2} \mathrm{P}_{2}{ }^{2} \\
\therefore \mathrm{T}_{1}(4)^{2}=\left(\mathrm{T}_{1}-0.009\right)(5)^{2} \\
\therefore 9 \mathrm{~T}_{1}=0.009 \times 25 \\
\therefore \mathrm{T}_{1}=0.025 \mathrm{~kg}-\mathrm{wt}
\end{array}
\)
\(
\begin{array}{l}
\therefore \mathrm{T}_{1} \mathrm{P}_{1}{ }^{2}=\mathrm{T}_{2} \mathrm{P}_{2}{ }^{2} \\
\therefore \mathrm{T}_{1}(4)^{2}=\left(\mathrm{T}_{1}-0.009\right)(5)^{2} \\
\therefore 9 \mathrm{~T}_{1}=0.009 \times 25 \\
\therefore \mathrm{T}_{1}=0.025 \mathrm{~kg}-\mathrm{wt}
\end{array}
\)
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