ExamBro
ExamBro
MHT CET · Physics · Nuclear Physics

In \(\mathrm{M}_{\mathrm{O}}\) is the mass of an oxygen isotope \({ }_8 \mathrm{O}^{17}\) and \(M_p\) and \(M_N\) are the mass of proton and mass of neutron respectively, then the nucleus binding energy of the isotope is

  1. A \(\mathrm{M}_{\mathrm{o}} \mathrm{C}^2\)
  2. B \(\left(\mathrm{M}_{\mathrm{O}}-8 \mathrm{M}_{\mathrm{p}}\right) \mathrm{C}^2\)
  3. C \(\left(\mathrm{M}_{\mathrm{O}}-17 \mathrm{M}_{\mathrm{N}}\right) \mathrm{C}^2\)
  4. D \(\left(\mathrm{M}_{\mathrm{o}}-8 \mathrm{M}_{\mathrm{p}}-9 \mathrm{M}_{\mathrm{N}}\right) \mathrm{C}^2\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\left(\mathrm{M}_{\mathrm{o}}-8 \mathrm{M}_{\mathrm{p}}-9 \mathrm{M}_{\mathrm{N}}\right) \mathrm{C}^2\)

Step-by-step Solution

Detailed explanation

Number of protons \(=8\)
Number of neutrons \(=17-8=9\)
Binding energy,
\(\begin{aligned}
B E & =\left(M_{\text {nucleus }}-M_{\text {nucleons }}\right) C^2 \\
& =\left(M_0-8 M_p-9 M_N\right) C^2
\end{aligned}\)