MHT CET · Physics · Nuclear Physics
In \(\mathrm{M}_{\mathrm{O}}\) is the mass of an oxygen isotope \({ }_8 \mathrm{O}^{17}\) and \(M_p\) and \(M_N\) are the mass of proton and mass of neutron respectively, then the nucleus binding energy of the isotope is
- A \(\mathrm{M}_{\mathrm{o}} \mathrm{C}^2\)
- B \(\left(\mathrm{M}_{\mathrm{O}}-8 \mathrm{M}_{\mathrm{p}}\right) \mathrm{C}^2\)
- C \(\left(\mathrm{M}_{\mathrm{O}}-17 \mathrm{M}_{\mathrm{N}}\right) \mathrm{C}^2\)
- D \(\left(\mathrm{M}_{\mathrm{o}}-8 \mathrm{M}_{\mathrm{p}}-9 \mathrm{M}_{\mathrm{N}}\right) \mathrm{C}^2\)
Answer & Solution
Correct Answer
(D) \(\left(\mathrm{M}_{\mathrm{o}}-8 \mathrm{M}_{\mathrm{p}}-9 \mathrm{M}_{\mathrm{N}}\right) \mathrm{C}^2\)
Step-by-step Solution
Detailed explanation
Number of protons \(=8\)
Number of neutrons \(=17-8=9\)
Binding energy,
\(\begin{aligned}
B E & =\left(M_{\text {nucleus }}-M_{\text {nucleons }}\right) C^2 \\
& =\left(M_0-8 M_p-9 M_N\right) C^2
\end{aligned}\)
Number of neutrons \(=17-8=9\)
Binding energy,
\(\begin{aligned}
B E & =\left(M_{\text {nucleus }}-M_{\text {nucleons }}\right) C^2 \\
& =\left(M_0-8 M_p-9 M_N\right) C^2
\end{aligned}\)
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