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MHT CET · Physics · Alternating Current

In LCR series circuit, when ' \(L\) ' is removed from the circuit, the phase difference between voltage and current in the circuit is \(\frac{\pi}{3}\). If ' \(C\) ' is removed from the circuit instead of \(L\) then phase difference is again \(\frac{\pi}{3}\). The power factor of the circuit is \(\left(\tan 60^{\circ}=\sqrt{3}\right)\)

  1. A \(\frac{\sqrt{3}}{2}\)
  2. B \(\sqrt{2}\)
  3. C \(\frac{1}{\sqrt{2}}\)
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(D) 1

Step-by-step Solution

Detailed explanation

For L removed (RC circuit): \(\tan \frac{\pi}{3} = \frac{X_C}{R} \implies \sqrt{3} = \frac{X_C}{R}\) For C removed (RL circuit): \(\tan \frac{\pi}{3} = \frac{X_L}{R} \implies \sqrt{3} = \frac{X_L}{R}\)