MHT CET · Physics · Alternating Current
In LCR series circuit, when ' \(L\) ' is removed from the circuit, the phase difference between voltage and current in the circuit is \(\frac{\pi}{3}\). If ' \(C\) ' is removed from the circuit instead of \(L\) then phase difference is again \(\frac{\pi}{3}\). The power factor of the circuit is \(\left(\tan 60^{\circ}=\sqrt{3}\right)\)
- A \(\frac{\sqrt{3}}{2}\)
- B \(\sqrt{2}\)
- C \(\frac{1}{\sqrt{2}}\)
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
For L removed (RC circuit): \(\tan \frac{\pi}{3} = \frac{X_C}{R} \implies \sqrt{3} = \frac{X_C}{R}\) For C removed (RL circuit): \(\tan \frac{\pi}{3} = \frac{X_L}{R} \implies \sqrt{3} = \frac{X_L}{R}\)
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