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MHT CET · Physics · Atomic Physics

In hydrogen emission spectrum, for any series, the principal quantum number is n. Corresponding maximum wavelength λ is (R = Rydberg’s constant)

  1. A R2n+1n2n+1
  2. B n2n+12R2n+1
  3. C n2n+1R2n+1
  4. D R2n+1n2n+12
Verified Solution

Answer & Solution

Correct Answer

(B) n2n+12R2n+1

Step-by-step Solution

Detailed explanation

In hydrogen emission spectrum, wavelength is given by
1λ=R1n12-1n22
For maximum wavelength of any principal quantum number n,
n1=nandn2=n+1
1λmax=R1n2-1n+12
=Rn+12-n2n2n+12
=Rn2+2n+1-n2n2n+12
1λmax=R22n+1n2n+12
λmax=n2n+12R2n+1