MHT CET · Physics · Atomic Physics
In hydrogen atom spectrum, when an electron jumps from second excited state to the first excited state, the wavelength of radiation emitted is ' \(\lambda\) '. If the electron jumps from the third excited state to the second orbit, the wavelength of radiation emitted will be \(20 \lambda / x\). The value of \(x\) is
- A \(18\)
- B \(27\)
- C \(21\)
- D \(36\)
Answer & Solution
Correct Answer
(B) \(27\)
Step-by-step Solution
Detailed explanation
\( \frac{1}{\lambda} = R \left( \frac{1}{2^2} - \frac{1}{3^2} \right) = R \left( \frac{1}{4} - \frac{1}{9} \right) = R \left( \frac{5}{36} \right) \) \( \frac{1}{\lambda'} = R \left( \frac{1}{2^2} - \frac{1}{4^2} \right) = R \left( \frac{1}{4} - \frac{1}{16} \right) = R \left( \frac{3}{16} \right) \)
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