MHT CET · Physics · Semiconductors
In common emitter mode of transistor, the d.c. current gain is 20 , the emitter
current is \(7 \mathrm{~mA}\). The collector current is
- A \(16 / 3 \mathrm{~mA}\)
- B \(13 / 3 \mathrm{~mA}\)
- C \(8 / 3 \mathrm{~mA}\)
- D \(20 / 3 \mathrm{~mA}\)
Answer & Solution
Correct Answer
(D) \(20 / 3 \mathrm{~mA}\)
Step-by-step Solution
Detailed explanation
\(\beta=\frac{I_{C}}{I_{B}}=20\)
\(\frac{I_{C}}{I_{E}-I_{C}}=20 \quad \frac{I_{E}-I_{C}}{I_{C}}=\frac{1}{20}\)
\(\frac{I_{E}}{I_{C}}-1=\frac{1}{20} \quad \frac{I_{E}}{I_{C}}=\frac{1}{20}+1=\frac{21}{20}\)
\(I_{C}=\frac{20}{21} \times 7=\frac{20}{3} \mathrm{~mA}\)
\(\frac{I_{C}}{I_{E}-I_{C}}=20 \quad \frac{I_{E}-I_{C}}{I_{C}}=\frac{1}{20}\)
\(\frac{I_{E}}{I_{C}}-1=\frac{1}{20} \quad \frac{I_{E}}{I_{C}}=\frac{1}{20}+1=\frac{21}{20}\)
\(I_{C}=\frac{20}{21} \times 7=\frac{20}{3} \mathrm{~mA}\)
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