MHT CET · Physics · Semiconductors
In common emitter amplifier, input resistance is \(1000 \Omega\), peak value of input signal voltage is \(5 \mathrm{mV}\) and \(\beta=60\). The peak value of output current is
- A \(0.5 \times 10^{-4} \mathrm{~A}\)
- B \(3 \times 10^{-4} \mathrm{~A}\)
- C \(2 \times 10^{-5} \mathrm{~A}\)
- D \(1 \times 10^{-5} \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(3 \times 10^{-4} \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
\(r_{L}=1000 \Omega\)
\(v_{i}=5 \mathrm{mV}=5 \times 10^{-3} \mathrm{~V}\)
\(\beta=60\)
\(I_{\text {input }}=\frac{5 \times 10^{-3}}{1000}=5 \times 10^{-6} \mathrm{~A}\)
\(\therefore I_{\text {output }}=60 \times 5 \times 10^{-6} \mathrm{~A}=300 \times 10^{-6} \mathrm{~A}\)
\(=3 \times 10^{-4} \mathrm{~A}\)
\(v_{i}=5 \mathrm{mV}=5 \times 10^{-3} \mathrm{~V}\)
\(\beta=60\)
\(I_{\text {input }}=\frac{5 \times 10^{-3}}{1000}=5 \times 10^{-6} \mathrm{~A}\)
\(\therefore I_{\text {output }}=60 \times 5 \times 10^{-6} \mathrm{~A}=300 \times 10^{-6} \mathrm{~A}\)
\(=3 \times 10^{-4} \mathrm{~A}\)
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