MHT CET · Physics · Semiconductors
In common emitter amplifier, a change of \(0.2 \mathrm{~mA}\) in the base current causes a change of \(5 \mathrm{~mA}\) in the collector current. If input resistance is \(2 \mathrm{k} \Omega\) and voltage gain is 75 , load resistance used in the circuit is
- A \(8 \mathrm{k} \Omega\)
- B \(4 \mathrm{k} \Omega\)
- C \(12 \mathrm{k} \Omega\)
- D \(6 \mathrm{k} \Omega\)
Answer & Solution
Correct Answer
(D) \(6 \mathrm{k} \Omega\)
Step-by-step Solution
Detailed explanation
\(
\beta=\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{b}}}=\frac{5}{0.2}=25
\)
Voltage gain, \(A_v=\beta \frac{R_L}{R_i}\)
\(
\therefore \mathrm{R}_{\mathrm{L}}=\frac{\mathrm{A}_{\mathrm{v}} \mathrm{R}_{\mathrm{i}}}{\beta}=\frac{75 \times 2}{25}=6 \mathrm{k} \Omega
\)
\beta=\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{b}}}=\frac{5}{0.2}=25
\)
Voltage gain, \(A_v=\beta \frac{R_L}{R_i}\)
\(
\therefore \mathrm{R}_{\mathrm{L}}=\frac{\mathrm{A}_{\mathrm{v}} \mathrm{R}_{\mathrm{i}}}{\beta}=\frac{75 \times 2}{25}=6 \mathrm{k} \Omega
\)
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