MHT CET · Physics · Atomic Physics

In Bohr's theory of Hydrogen atom, the electron jumps from higher orbit $n$ to lower orbit $p$. The wavelength will be maximum for the transition

A $n = 5 t o p = 4$
B $n = 4 t o p = 3$
C $n = 3 t o p = 2$
D $n = 2 t o p = 1$

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Answer & Solution

Correct Answer

(A) $n = 5 t o p = 4$

Step-by-step Solution

Detailed explanation

According to Bohr's theory the wavelength of radiation emitted is given by

\frac{1}{λ} = R (\frac{1}{n i^{2}} - \frac{1}{n f^{2}})

For

n_{i} = 5 a n d n_{f} = 4

, the wavelength emitted will be longest as energy difference

∆ E = E_{5} - E_{4}

is very small.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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In Bohr's theory of Hydrogen atom, the electron jumps from higher orbit \(n\) to lower orbit \(p\). The wavelength will be maximum for the transition

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