MHT CET · Physics · Wave Optics
In biprism experiment, if \(5^{\text {th }}\) bright band with wavelength \(\lambda_1^{\prime}\) coincides with \(6^{\text {th }}\) dark band with wavelength \(\lambda_2{ }^{\prime}\) then the ratio \(\left(\frac{\lambda_2}{\lambda_1}\right)\) is
- A \(\frac{9}{7}\)
- B \(\frac{7}{9}\)
- C \(\frac{10}{11}\)
- D \(\frac{11}{10}\)
Answer & Solution
Correct Answer
(C) \(\frac{10}{11}\)
Step-by-step Solution
Detailed explanation
The fifth bright band will be:
\(
\mathrm{y}_5=\frac{5 \lambda_1 \mathrm{D}}{\mathrm{d}}
\)
\(\therefore \quad\) The sixth dark band will be:
\(
\begin{aligned}
& \mathrm{y}_6{ }^{\prime}=\frac{11 \lambda_2 \mathrm{D}}{2 \mathrm{~d}} \\
& \text { Given: } \mathrm{y}_5=\mathrm{y}_6^{\prime} \\
\therefore \quad \frac{5 \lambda_1 \mathrm{D}}{\mathrm{d}} & =\frac{11 \lambda_2 \mathrm{D}}{2 \mathrm{~d}} \\
5 \lambda_1 & =\frac{11 \lambda_2}{2} \\
\frac{\lambda_2}{\lambda_1} & =\frac{10}{11}
\end{aligned}
\)
\(
\mathrm{y}_5=\frac{5 \lambda_1 \mathrm{D}}{\mathrm{d}}
\)
\(\therefore \quad\) The sixth dark band will be:
\(
\begin{aligned}
& \mathrm{y}_6{ }^{\prime}=\frac{11 \lambda_2 \mathrm{D}}{2 \mathrm{~d}} \\
& \text { Given: } \mathrm{y}_5=\mathrm{y}_6^{\prime} \\
\therefore \quad \frac{5 \lambda_1 \mathrm{D}}{\mathrm{d}} & =\frac{11 \lambda_2 \mathrm{D}}{2 \mathrm{~d}} \\
5 \lambda_1 & =\frac{11 \lambda_2}{2} \\
\frac{\lambda_2}{\lambda_1} & =\frac{10}{11}
\end{aligned}
\)
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