MHT CET · Physics · Wave Optics

In baptism experiment, the distance between source and eyepiece is $1.2 m,$ the distance between two virtual sources is $0.84 m m .$ Then, the wavelength of light used if eyepiece is to be moved transverselythrough a distance of $2.799 c m$ to shift $30$ fringes is

A $6533 Å$
B $6537 Å$
C $6535 Å$
D $6351 Å$

Verified Solution

Answer & Solution

Correct Answer

(D) $6351 Å$

Step-by-step Solution

Detailed explanation

y = n . \frac{λ D}{d}

2.799 \times 10^{- 2} = \frac{(30) λ (1.2)}{0.84 \times 10^{- 3}}

\Rightarrow λ = 6351 Å

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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In baptism experiment, the distance between source and eyepiece is 1.2m, the distance between two virtual sources is 0.84mm. Then, the wavelength of light used if eyepiece is to be moved transverselythrough a distance of 2.799cm to shift 30 fringes is

Step-by-step Solution

In baptism experiment, the distance between source and eyepiece is $1.2 m,$ the distance between two virtual sources is $0.84 m m .$ Then, the wavelength of light used if eyepiece is to be moved transverselythrough a distance of $2.799 c m$ to shift $30$ fringes is