MHT CET · Physics · Alternating Current
In an LCR series circuit, if the angular frequency is gradually in creased then match the following columns
- A \((\mathrm{A})-(\mathrm{iv}),(\mathrm{B})-(\mathrm{i}),(\mathrm{C})-(\mathrm{ii}),(\mathrm{D})-(\mathrm{iii})\)
- B (A) - (i), (B) - (iii), (C) - (iv), (D) - (ii)
- C \((\mathrm{A})-(\mathrm{ii}),(\mathrm{B})-(\mathrm{iii}),(\mathrm{C})-(\mathrm{i}),(\mathrm{D})-(\mathrm{iv})\)
- D \((A)-(i),(B)-(i v),(C)-(i i),(D)-(i i i)\)
Answer & Solution
Correct Answer
(A) \((\mathrm{A})-(\mathrm{iv}),(\mathrm{B})-(\mathrm{i}),(\mathrm{C})-(\mathrm{ii}),(\mathrm{D})-(\mathrm{iii})\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{X}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}, \text { so } \mathrm{X}_{\mathrm{C}} \propto \frac{1}{\omega} \\ & \therefore(\mathrm{A})-(\mathrm{iv}) \\ & \mathrm{X}_{\mathrm{L}}=\omega \mathrm{L}, \text { so } \mathrm{X}_{\mathrm{L}} \propto \omega \\ & \therefore(\mathrm{B})-(\mathrm{i})\end{aligned}\)
And \(\mathrm{R}\) is not a function of \(\omega\)
\(\therefore(\mathrm{C})-(\mathrm{ii})\)
Impedence \(\mathrm{Z}\) is the minimum at resonance frequency.
\(\therefore(\mathrm{D})-(\mathrm{iii})\)
And \(\mathrm{R}\) is not a function of \(\omega\)
\(\therefore(\mathrm{C})-(\mathrm{ii})\)
Impedence \(\mathrm{Z}\) is the minimum at resonance frequency.
\(\therefore(\mathrm{D})-(\mathrm{iii})\)
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