MHT CET · Physics · Alternating Current
In an \(L R\) circuit, the value of \(L\) is \(\left(\frac{0 \cdot 3}{\pi}\right)\) henry and the value of \(R\) is \(40 \Omega\), If in the circuit, an alternating e.m.f of 230 V at 50 cycles per second is connected, the impedance of the circuit and current will be respectively
- A \(12.5 \Omega, 9.2 \mathrm{~A}\)
- B \(46.4 \Omega, 6.4 \mathrm{~A}\)
- C \(23.2 \Omega, 5 \mathrm{~A}\)
- D \(50 \Omega, 4.6 \mathrm{~A}\)
Answer & Solution
Correct Answer
(D) \(50 \Omega, 4.6 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
\(X_L = 2 \pi f L = 2 \pi (50) \left(\frac{0.3}{\pi}\right) = 30 \, \Omega\) \(Z = \sqrt{R^2 + X_L^2} = \sqrt{40^2 + 30^2} = \sqrt{1600 + 900} = \sqrt{2500} = 50 \, \Omega\)
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