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MHT CET · Physics · Thermodynamics

In an isochoric process if \(t_1=27^{\circ} \mathrm{C}\) and, \(t_2=127^{\circ} \mathrm{C}\) then \(\frac{P_1}{P_2}\) will be equal to \(\left[P_1\right.\) and \(P_2\) are the pressures at \(t_1{ }^{\circ} \mathrm{C}\) and \(t_2^{\circ} \mathrm{C}\) respectively]

  1. A \(\frac{9}{59}\)
  2. B \(\frac{4}{3}\)
  3. C \(\frac{3}{4}\)
  4. D \(\frac{2}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{3}{4}\)

Step-by-step Solution

Detailed explanation

At constant volume \(P \propto T \therefore \frac{P_1}{P_2}=\frac{T_1}{T_2}=\frac{300}{400}=\frac{3}{4}\)