MHT CET · Physics · Thermodynamics
In an isochoric process if \(t_1=27^{\circ} \mathrm{C}\) and, \(t_2=127^{\circ} \mathrm{C}\) then \(\frac{P_1}{P_2}\) will be equal to \(\left[P_1\right.\) and \(P_2\) are the pressures at \(t_1{ }^{\circ} \mathrm{C}\) and \(t_2^{\circ} \mathrm{C}\) respectively]
- A \(\frac{9}{59}\)
- B \(\frac{4}{3}\)
- C \(\frac{3}{4}\)
- D \(\frac{2}{3}\)
Answer & Solution
Correct Answer
(C) \(\frac{3}{4}\)
Step-by-step Solution
Detailed explanation
At constant volume \(P \propto T \therefore \frac{P_1}{P_2}=\frac{T_1}{T_2}=\frac{300}{400}=\frac{3}{4}\)
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