MHT CET · Physics · Alternating Current
In an ideal step-down transformer, out of the following quantities, which quantity increases in the secondary coil?
- A Power
- B Voltage
- C Current
- D Frequency
Answer & Solution
Correct Answer
(C) Current
Step-by-step Solution
Detailed explanation
For an ideal transformer,
\(
\frac{\mathrm{V}_{\mathrm{s}}}{\mathrm{V}_{\mathrm{p}}}=\frac{\mathrm{I}_{\mathrm{p}}}{\mathrm{I}_{\mathrm{s}}}
\)
Hence, if \(\mathrm{V}_{\mathrm{s}} < \mathrm{V}_{\mathrm{p}}\) then \(\mathrm{I}_{\mathrm{p}} < \mathrm{I}_{\mathrm{s}}\)
\(
\frac{\mathrm{V}_{\mathrm{s}}}{\mathrm{V}_{\mathrm{p}}}=\frac{\mathrm{I}_{\mathrm{p}}}{\mathrm{I}_{\mathrm{s}}}
\)
Hence, if \(\mathrm{V}_{\mathrm{s}} < \mathrm{V}_{\mathrm{p}}\) then \(\mathrm{I}_{\mathrm{p}} < \mathrm{I}_{\mathrm{s}}\)
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