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MHT CET · Physics · Mathematics in Physics

In an experiment four quantities \(p, q, r\) and \(s\) are measured with percentage \(3 \%, 2 \%, 3 \%\) and \(1 \%\) respectively. Quantity ' A ' is calculated as follows \(\mathrm{A}=\frac{\mathrm{pq}^2}{\mathrm{r}^2 \mathrm{~s}^4}\), the percentage error in ' A ' is

  1. A \(17 \%\)
  2. B \(12 \%\)
  3. C \(18 \%\)
  4. D \(19 \%\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(17 \%\)

Step-by-step Solution

Detailed explanation

\(\frac{\Delta A}{A}\% = 1 \cdot \frac{\Delta p}{p}\% + 2 \cdot \frac{\Delta q}{q}\% + 2 \cdot \frac{\Delta r}{r}\% + 4 \cdot \frac{\Delta s}{s}\%\) \(\frac{\Delta A}{A}\% = 1(3\%) + 2(2\%) + 2(3\%) + 4(1\%)\)