MHT CET · Physics · Ray Optics
In an equilateral prism the ray undergoes minimum deviation when it is incident at an angle of \(50^{\circ}\). The angle of minimum deviation is
- A \(50^{\circ}\)
- B \(40^{\circ}\)
- C \(25^{\circ}\)
- D \(20^{\circ}\)
Answer & Solution
Correct Answer
(B) \(40^{\circ}\)
Step-by-step Solution
Detailed explanation
When a ray undergoes minimum deviation,
\(i=\frac{A+\delta_m}{2}\)
For an equilateral triangle,
\(\begin{aligned}
& A=60^{\circ} \\
\therefore \quad & 50=\frac{60+\delta_m}{2} \\
\therefore \quad & \delta_m=40^{\circ}
\end{aligned}\)
\(i=\frac{A+\delta_m}{2}\)
For an equilateral triangle,
\(\begin{aligned}
& A=60^{\circ} \\
\therefore \quad & 50=\frac{60+\delta_m}{2} \\
\therefore \quad & \delta_m=40^{\circ}
\end{aligned}\)
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