MHT CET · Physics · Current Electricity
In an atom, electron of charge (-e) performs U.C.M. around a stationary positively charged nucleus, with period of revolution 'T'. If 'r' is the radius of the orbit of the electron and ' \(\mathrm{v}^{\prime}\) is the orbital velocity, then the circulating current (I) is proportional to
- A \(\mathrm{e}^{1} \mathrm{r}^{-1} \mathrm{v}^{-1}\)
- B \(\mathrm{e}^{1} \mathrm{r}^{1} \mathrm{~V}^{-1}\)
- C \(\mathrm{e}^{1} \mathrm{~V}^{1} \mathrm{r}^{-1}\)
- D \(\mathrm{v}^{1} \mathrm{r}^{1} \mathrm{e}^{-1}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{e}^{1} \mathrm{~V}^{1} \mathrm{r}^{-1}\)
Step-by-step Solution
Detailed explanation
In an atom, electron of charge \((-e)\) perform U.C.M. around a stationary positively charged nucleus, with period of revolution \(\mathrm{'T'}\).
If \(' r^{\prime}\) is the radius of the orbit of the electron and ' \(v\) ' is the orbital velocity, then the circulating current \(\mathrm{(I)}\) is proportional to \(\underline{\mathbf{e}}^{\mathbf{1}}\) \(\underline{\mathbf{v}}^{\mathbf{1}}\) \(\underline{\mathbf{r}}^{\mathbf{-1}}\).

\(\frac{2 \pi r}{\mathrm{T}}=v\)
\(\mathrm{I}=\frac{\mathrm{e}}{\mathrm{T}}=\frac{\mathrm{ev}}{2 \pi \mathrm{r}}=\mathrm{e}^{1} \mathrm{v}^{1} \mathrm{r}^{-1} \frac{1}{2} \pi\)
\(\mathrm{I} \propto e^{1} v^{1} r^{-1}\)
If \(' r^{\prime}\) is the radius of the orbit of the electron and ' \(v\) ' is the orbital velocity, then the circulating current \(\mathrm{(I)}\) is proportional to \(\underline{\mathbf{e}}^{\mathbf{1}}\) \(\underline{\mathbf{v}}^{\mathbf{1}}\) \(\underline{\mathbf{r}}^{\mathbf{-1}}\).

\(\frac{2 \pi r}{\mathrm{T}}=v\)
\(\mathrm{I}=\frac{\mathrm{e}}{\mathrm{T}}=\frac{\mathrm{ev}}{2 \pi \mathrm{r}}=\mathrm{e}^{1} \mathrm{v}^{1} \mathrm{r}^{-1} \frac{1}{2} \pi\)
\(\mathrm{I} \propto e^{1} v^{1} r^{-1}\)
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